Specific volume of cylindrical virus particle

Some Basic Concepts of Chemistry

Specific volume of cylindrical virus particle is 6.02 × 10

^{- 2}

cc/gm. whose radius and length 7 Å & 10 Å respectively. If NA = 6.02 × 10

^{23}

, find molecular weight of virus

A. 3.08 × 10

^{3}

kg/mol
B. 3.08 × 10

^{4}

kg/mol
C. 1.54 × 10

^{4}

kg/mol
D. 15.4 kg/mol

Specific volume (volume of 1 gm) of
cylindrical virus particle = 6.02 × 10

^{- 2}

cc/gm
Radius of virus (r) = 7 Å = 7 × 10

^{- 8}

cm
Length of virus = 10 × 10

^{- 8}

cm
Volume of virus =

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